Given a set of lines and a rectangular area of interest, the task is to remove lines which are outside the area of interest and clip the lines which are partially inside the area.
Input : Rectangular area of interest (Defined by below four values which are coordinates of bottom left and top right) x_min = 4, y_min = 4, x_max = 10, y_max = 8 A set of lines (Defined by two corner coordinates) line 1 : x1 = 5, y1 = 5, x2 = 7, y2 = 7 Line 2 : x1 = 7, y1 = 9, x2 = 11, y2 = 4 Line 2 : x1 = 1, y1 = 5, x2 = 4, y2 = 1 Output : Line 1 : Accepted from (5, 5) to (7, 7) Line 2 : Accepted from (7.8, 8) to (10, 5.25) Line 3 : Rejected
Cohen-Sutherland algorithm divides a two-dimensional space into 9 regions and then efficiently determines the lines and portions of lines that are inside the given rectangular area.
The algorithm can be outlines as follows:-
Nine regions are created, eight "outside" regions and one "inside" region. For a given line extreme point (x, y), we can quickly find its region's four bit code. Four bit code can be computed by comparing x and y with four values (x_min, x_max, y_min and y_max). If x is less than x_min then bit number 1 is set. If x is greater than x_max then bit number 2 is set. If y is less than y_min then bit number 3 is set. If y is greater than y_max then bit number 4 is set
There are three possible cases for any given line.
- Completely inside the given rectangle : Bitwise OR of region of two end points of line is 0 (Both points are inside the rectangle)
- Completely outside the given rectangle : Both endpoints share at least one outside region which implies that the line does not cross the visible region. (bitwise AND of endpoints != 0).
- Partially inside the window : Both endpoints are in different regions. In this case, the algorithm finds one of the two points that is outside the rectangular region. The intersection of the line from outside point and rectangular window becomes new corner point and the algorithm repeats
Step 1 : Assign a region code for two endpoints of given line. Step 2 : If both endpoints have a region code 0000 then given line is completely inside. Step 3 : Else, perform the logical AND operation for both region codes. Step 3.1 : If the result is not 0000, then given line is completely outside. Step 3.2 : Else line is partially inside. Step 3.2.1 : Choose an endpoint of the line that is outside the given rectangle. Step 3.2.2 : Find the intersection point of the rectangular boundary (based on region code). Step 3.2.3 : Replace endpoint with the intersection point and update the region code. Step 3.2.4 : Repeat step 2 until we find a clipped line either trivially accepted or trivially rejected. Step 4 : Repeat step 1 for other lines
Below is implementation of above steps.
Line accepted from 5.00, 5.00 to 7.00, 7.00 Line accepted from 7.80, 8.00 to 10.00, 5.25 Line rejected
Below is C++ code with Graphics using graphics.h
The Cohen–Sutherland algorithm can be used only on a rectangular clip window. For other convex polygon clipping windows, Cyrus–Beck algorithm is used. We will be discussing Cyrus–Beck Algorithm in next set.
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- Line Clipping | Set 2 (Cyrus Beck Algorithm)
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- Point Clipping Algorithm in Computer Graphics
- Polygon Clipping | Sutherland–Hodgman Algorithm
- Methods for Text Clipping in Computer Graphics
- Slope of the line parallel to the line with the given slope
- DDA Line generation Algorithm in Computer Graphics
- Klee's Algorithm (Length Of Union Of Segments of a line)
- Bresenham’s Line Generation Algorithm
- Mid-Point Line Generation Algorithm
- Anti-aliased Line | Xiaolin Wu's algorithm
- Bresenham's Algorithm for 3-D Line Drawing
- Comparions between DDA and Bresenham Line Drawing algorithm
- Represent a given set of points by the best possible straight line
- How to check if two given line segments intersect?
- Given n line segments, find if any two segments intersect
- Count maximum points on same line
- Find an Integer point on a line segment with given two ends
- Scan-line Polygon filling using OPENGL in C
- Program to find line passing through 2 Points
Improved By : imkiller