Lex program to count words that are less than 10 and greater than 5

Problem: Write a Lex program to count words that are less than 10 and greater than 5.

Explanation:
Lex is a computer program that generates lexical analyzers. Lex reads an input stream specifying the lexical analyzer and outputs source code implementing the lexer in the C programming language.

The commands for executing the lex program are:



lex abc.l (abc is the file name)
cc lex.yy.c -efl
./a.out

Let’s see Lex Program to count words that are less than 10 and greater than 5.

Examples:

Input: geeksforgeeks hey google test lays
Output: 1 

Below is the implementation:

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/*lex code to count words that are less than 10
    - and greater than 5 */
  
%{
  int len=0, counter=0;
%}
  
%%
[a-zA-Z]+ { len=strlen(yytext);
            if(len<10 && len>5)
              {counter++;} }
%%
  
int yywrap (void )
 {
    return 1;
 }
  
int main()
 {
  printf("Enter the string:");
  yylex();
  printf("\n %d", counter);
  return 0;
 }

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Output:



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