Given are two chords which are equally inclined through the diameter of the circle. Length of one chord is given. The task is to find the length of another chord.

**Examples:**

Input:z = 48Output:48 degreesInput:z = 93Output:93 degrees

**Approach**:

- Let
**AB**and**AC**be the two chords of the circle having the center at**O**. - now, in the figure we see,
**OL**is perpendicular to**AB**and**OM**is perpendicular to**AC** - in triangle
**OLA**and triangle**OMA**,**angle OLA = angle OMA = 90 degrees****angle OAL = angle OAM**(as the chords are inclined equally through the diameter)**OA = OA**(common side) - so triangle
**OLA**and triangle**OMA**are congruent to each other. - So,
**OL = OM** - and we know, equal chords are equidistant from the center, so Length of
**AB**and**AC**will be same.

If two chords are equally inclined through the diameter of the same circle, then they are of equal length.

Below is the implementation of the above approach:

C++

`// C++ program to find ` `// the length of the chord the circle ` `// if length of the another chord ` `// which is equally inclined ` `// through the diameter is given ` ` ` `#include <bits/stdc++.h> ` `using` `namespace` `std; `
` ` `void` `lengchord(` `int` `z) `
`{ ` ` ` `cout << ` `"The length is "`
` ` `<< z << endl; `
`} ` ` ` `// Driver code ` `int` `main() `
`{ ` ` ` `int` `z = 48; `
` ` `lengchord(z); `
` ` `return` `0; `
`} ` |

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Java

`// Java program to find ` `// the length of the chord the circle ` `// if length of the another chord ` `// which is equally inclined ` `// through the diameter is given ` `import` `java.io.*; `
` ` `class` `GFG `
`{ ` ` ` `static` `void` `lengchord(` `int` `z) `
`{ ` ` ` `System.out.println (` `"The length is "` `+ z ); `
`} ` ` ` `// Driver code ` `public` `static` `void` `main (String[] args) `
`{ ` ` ` ` ` `int` `z = ` `48` `; `
` ` `lengchord(z); `
`} ` `} ` ` ` `// The code has been contributed by ajit. ` |

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Python3

`# Python3 program to find ` `# the length of the chord of the circle ` `# if length of the other chord ` `# which is equally inclined ` `# through the diameter is given ` `def` `lengchord(z): `
` ` `print` `(` `"The length is "` `, end ` `=` `""); `
` ` `print` `(z); `
` ` `# Driver code ` `z ` `=` `48` `; `
`lengchord(z); ` ` ` `# This code is contributed ` `# by Princi Singh ` |

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C#

`// C# program to find ` `// the length of the chord the circle ` `// if length of the another chord ` `// which is equally inclined ` `// through the diameter is given ` `using` `System; `
` ` `class` `GFG `
`{ ` ` ` `static` `void` `lengchord(` `int` `z) `
`{ ` ` ` `Console.WriteLine(` `"The length is "` `+ z ); `
`} ` ` ` `// Driver code ` `static` `public` `void` `Main () `
`{ ` ` ` ` ` `int` `z = 48; `
` ` `lengchord(z); `
`} ` `} ` ` ` `// The code has been contributed by Tushil ` |

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**Output:**

The length is 48

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