# Largest right circular cylinder within a frustum

Given a frustum of height , top-radius & base-radius . The task is to find the volume of biggest right circular cylinder that can be inscribed within it.

Examples:

```Input  : r = 5, R = 10, h = 4
Output : 314

Input : r = 7, R = 11, h = 6
Output : 923.16
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach:
Let:

• The height of the cylinder = h1
• Radius of the cylinder = r1

From the figure it is clear that:

• Height of the cylinder = Height of frustum

So,

```h1 = h
r1 = r```

Below is the implementation of the above approach:

## C++

 `// C++ Program to find the biggest right circular cylinder ` `// that can be fit within a frustum ` `#include ` `using` `namespace` `std; ` ` `  `// Function to find the biggest right circular cylinder ` `float` `cyl(``float` `r, ``float` `R, ``float` `h) ` `{ ` `    ``// radii and height cannot be negative ` `    ``if` `(h < 0 && r < 0 && R < 0) ` `        ``return` `-1; ` ` `  `    ``// radius of right circular cylinder ` `    ``float` `r1 = r; ` `    ``// height of right circular cylinder ` `    ``float` `h1 = h; ` `    ``// volume of right circular cylinder ` `    ``float` `V = 3.14 * ``pow``(r1, 2) * h1; ` ` `  `    ``return` `V; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``float` `r = 7, R = 11, h = 6; ` ` `  `    ``cout << cyl(r, R, h) << endl; ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java Program to find the biggest right circular cylinder ` `// that can be fit within a frustum ` ` `  `import` `java.io.*; ` ` `  `class` `GFG { ` ` `  ` `  `// Function to find the biggest right circular cylinder ` ` ``static` `float` `cyl(``float` `r, ``float` `R, ``float` `h) ` `{ ` `    ``// radii and height cannot be negative ` `    ``if` `(h < ``0` `&& r < ``0` `&& R < ``0``) ` `        ``return` `-``1``; ` ` `  `    ``// radius of right circular cylinder ` `    ``float` `r1 = r; ` `    ``// height of right circular cylinder ` `    ``float` `h1 = h; ` `    ``// volume of right circular cylinder ` `    ``float` `V = (``float``)(``3.14` `* Math.pow(r1, ``2``) * h1); ` ` `  `    ``return` `V; ` `} ` ` `  `// Driver code ` `    ``public` `static` `void` `main (String[] args) { ` `            ``float` `r = ``7``, R = ``11``, h = ``6``; ` ` `  `    ``System.out.print( cyl(r, R, h)); ` `    ``} ` `} ` `// This code is contributed by anuj_67.. `

## Python3

 `# Python3 Program to find the biggest right circular cylinder ` `# that can be fit within a frustum ` ` `  `# Function to find the biggest right circular cylinder ` `def` `cyl(r, R, h) : ` ` `  `    ``# radii and height cannot be negative ` `    ``if` `(h < ``0` `and` `r < ``0` `and` `R < ``0``) : ` `        ``return` `-``1` ` `  `    ``# radius of right circular cylinder ` `    ``r1 ``=` `r ` `    ``# height of right circular cylinder ` `    ``h1 ``=` `h ` `    ``# volume of right circular cylinder ` `    ``V ``=` `3.14` `*` `pow``(r1, ``2``) ``*` `h1 ` ` `  `    ``return` `round``(V,``2``) ` ` `  ` `  `# Driver code ` `if` `__name__ ``=``=` `"__main__"` `: ` ` `  `    ``r, R, h ``=` `7``, ``11``, ``6` ` `  `    ``print``(cyl(r, R, h)) ` ` `  `# This code is contributed by Ryuga `

## C#

 `// C# Program to find the biggest right circular cylinder ` `// that can be fit within a frustum ` `using` `System; ` ` `  `class` `GFG { ` ` `  ` `  `// Function to find the biggest right circular cylinder ` `static` `float` `cyl(``float` `r, ``float` `R, ``float` `h) ` `{ ` `    ``// radii and height cannot be negative ` `    ``if` `(h < 0 && r < 0 && R < 0) ` `        ``return` `-1; ` ` `  `    ``// radius of right circular cylinder ` `    ``float` `r1 = r; ` `    ``// height of right circular cylinder ` `    ``float` `h1 = h; ` `    ``// volume of right circular cylinder ` `    ``float` `V = (``float``)(3.14 * Math.Pow(r1, 2) * h1); ` ` `  `    ``return` `V; ` `} ` ` `  `// Driver code ` `    ``public` `static` `void` `Main () { ` `            ``float` `r = 7, R = 11, h = 6; ` ` `  `    ``Console.WriteLine( cyl(r, R, h)); ` `    ``} ` `} ` `// This code is contributed by anuj_67.. `

## PHP

 `

Output:

```923.16
```

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