# Largest right circular cylinder within a cube

Given a cube of side length a. The task is to find the volume of biggest right circular cylinder that can be inscribed within it.

Examples:

```Input :  a = 4
Output : 50.24

Input : a = 5
Output : 98.125
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach:
Let:

• The height of the cylinder is h.
• Radius of the cylinder be r.

From the diagram it is clear that:

• The height of the cylinder = side of cube
• Radius of the cylinder = side of the cube/2

So,

```h = a
r = a/2```

Below is the implementation of the above approach:

## C++

 `// C++ Program to find the biggest right ` `// circular cylinder that can be fit within a cube ` `#include ` `using` `namespace` `std; ` ` `  `// Function to find the biggest right circular cylinder ` `float` `findVolume(``float` `a) ` `{ ` `    ``// side cannot be negative ` `    ``if` `(a < 0) ` `        ``return` `-1; ` ` `  `    ``// radius of right circular cylinder ` `    ``float` `r = a / 2; ` ` `  `    ``// height of right circular cylinder ` `    ``float` `h = a; ` ` `  `    ``// volume of right circular cylinder ` `    ``float` `V = 3.14 * ``pow``(r, 2) * h; ` ` `  `    ``return` `V; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``float` `a = 5; ` ` `  `    ``cout << findVolume(a) << endl; ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java Program to find the biggest right ` `// circular cylinder that can be fit within a cube ` ` `  `import` `java.io.*; ` ` `  `class` `GFG { ` `   `  ` `  `// Function to find the biggest right circular cylinder ` ` ``static` `float` `findVolume(``float` `a) ` `{ ` `    ``// side cannot be negative ` `    ``if` `(a < ``0``) ` `        ``return` `-``1``; ` ` `  `    ``// radius of right circular cylinder ` `    ``float` `r = a / ``2``; ` ` `  `    ``// height of right circular cylinder ` `    ``float` `h = a; ` ` `  `    ``// volume of right circular cylinder ` `    ``float` `V = (``float``)(``3.14` `* Math.pow(r, ``2``) * h); ` ` `  `    ``return` `V; ` `} ` ` `  `// Driver code ` ` `  ` `  `    ``public` `static` `void` `main (String[] args) { ` `            ``float` `a = ``5``; ` ` `  `    ``System.out.print(findVolume(a)); ` `    ``} ` `} ` `// This code is contributed by anuj_67.. `

## Python3

 `# Python3 Program to find the biggest  ` `# right circular cylinder that can be  ` `# fit within a cube  ` ` `  `# Function to find the biggest right ` `# circular cylinder  ` `def` `findVolume(a) : ` ` `  `    ``# side cannot be negative  ` `    ``if` `(a < ``0``) :  ` `        ``return` `-``1` ` `  `    ``# radius of right circular cylinder  ` `    ``r ``=` `a ``/` `2` ` `  `    ``# height of right circular cylinder  ` `    ``h ``=` `a ` ` `  `    ``# volume of right circular cylinder  ` `    ``V ``=` `3.14` `*` `pow``(r, ``2``) ``*` `h  ` ` `  `    ``return` `V  ` ` `  `# Driver code  ` `if` `__name__ ``=``=` `"__main__"` `:  ` ` `  `    ``a ``=` `5` ` `  `    ``print``(findVolume(a)) ` ` `  `# This code is contributed by Ryuga `

## C#

 `// C# Program to find the biggest right ` `// circular cylinder that can be fit within a cube ` ` `  `using` `System; ` `class` `GFG { ` ` `  ` `  `// Function to find the biggest right circular cylinder ` `static` `float` `findVolume(``float` `a) ` `{ ` `    ``// side cannot be negative ` `    ``if` `(a < 0) ` `        ``return` `-1; ` ` `  `    ``// radius of right circular cylinder ` `    ``float` `r = a / 2; ` ` `  `    ``// height of right circular cylinder ` `    ``float` `h = a; ` ` `  `    ``// volume of right circular cylinder ` `    ``float` `V = (``float``)(3.14 * Math.Pow(r, 2) * h); ` ` `  `    ``return` `V; ` `} ` ` `  `// Driver code ` ` `  ` `  `    ``public` `static` `void` `Main () { ` `            ``float` `a = 5; ` ` `  `   ``Console.WriteLine(findVolume(a)); ` `    ``} ` `} ` `// This code is contributed by anuj_67.. `

## PHP

 `

Output:

```98.125
```

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