Largest Even and Odd N-digit numbers

Given an integer N, the task is to find the largest even and odd N-digit numbers.

Examples:

Input: N = 4
Output:
Even = 9998
Odd = 9999

Input: N = 2
Output:
Even = 98
Odd = 99

Approach:



  • Largest N-digit even number will be (10n) – 2 because the series for different values of N will be 8, 98, 998, 9998, …..
  • Similarly, largest N-digit odd number will be (10n) – 1 for the series 9, 99, 999, 9999, …..

Below is the implementation of the above approach:

C++

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// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to print the largest n-digit
// even and odd numbers
void findNumbers(int n)
{
    int odd = pow(10, n) - 1;
    int even = odd - 1;
    cout << "Even = " << even << endl;
    cout << "Odd = " << odd;
}
  
// Driver code
int main()
{
    int n = 4;
    findNumbers(n);
  
    return 0;
}

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Java














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// Java implementation of the approach 


class GFG { 


  


    // Function to print the largest n-digit 


    // even and odd numbers 


    static void findNumbers(int n) 


    { 


        int odd = (int)Math.pow(10, n) - 1; 


        int even = odd - 1; 


        System.out.println("Even = " + even); 


        System.out.print("Odd = " + odd); 


    } 


  


    // Driver code 


    public static void main(String args[]) 


    { 


        int n = 4; 


        findNumbers(n); 


    } 


} 



















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C#














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// C# implementation of the approach 


using System; 


class GFG { 


  


    // Function to print the largest n-digit 


    // even and odd numbers 


    static void findNumbers(int n) 


    { 


        int odd = (int)Math.Pow(10, n) - 1; 


        int even = odd - 1; 


        Console.WriteLine("Even = " + even); 


        Console.Write("Odd = " + odd); 


    } 


  


    // Driver code 


    public static void Main() 


    { 


        int n = 4; 


        findNumbers(n); 


    } 


} 



















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Python3














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# Python3 implementation of the approach 


  


# Function to print the largest n-digit 


# even and odd numbers 


def findNumbers(n): 


  


    odd = pow(10, n) - 1


    even = odd - 1


    print("Even = ", even) 


    print("Odd = ", odd) 


  


# Driver code 


n = 4


findNumbers(n) 


  


# This code is contributed by ihritik 



















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PHP














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<?php 


// PHP implementation of the approach 


  


// Function to print the largest n-digit 


// even and odd numbers 


function findNumbers($n) 


{ 


    $odd = pow(10, $n) - 1; 


    $even = $odd - 1; 


    echo "Even = $even \n"; 


    echo "Odd = $odd"; 


} 


  


// Driver code 


$n = 4 ; 


findNumbers($n); 


  


// This code is contributed by ihritik 


?> 



















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Output:


Even = 9998
Odd = 9999







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