Given an integer N, the task is to find the largest even and odd N-digit numbers.
Input: N = 4
Even = 9998
Odd = 9999
Input: N = 2
Even = 98
Odd = 99
- Largest N-digit even number will be (10n) – 2 because the series for different values of N will be 8, 98, 998, 9998, …..
- Similarly, largest N-digit odd number will be (10n) – 1 for the series 9, 99, 999, 9999, …..
Below is the implementation of the above approach:
Even = 9998 Odd = 9999
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Improved By : ihritik