# Largest cube that can be inscribed within a right circular cylinder

Given here is a right circular cylinder of height **h** and radius **r**. The task is to find the **volume **of biggest cube that can be inscribed within it.

**Examples**:

Input: h = 3, r = 2Output: volume = 27Input: h = 5, r = 4Output: volume = 125

**Approach**: From the figure, it can be clearly understand that **side of the cube = height of the cylinder**.

So, the **volume = (height)^3**

Below is the implementation of the above approach:

## C++

`// C++ Program to find the biggest cube ` `// inscribed within a right circular cylinder ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to find the volume of the cube ` `float` `cube(` `float` `h, ` `float` `r) ` `{ ` ` ` ` ` `// height and radius cannot be negative ` ` ` `if` `(h < 0 && r < 0) ` ` ` `return` `-1; ` ` ` ` ` `// volume of the cube ` ` ` `float` `a = ` `pow` `(h, 3); ` ` ` ` ` `return` `a; ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `float` `h = 5, r = 4; ` ` ` `cout << cube(h, r) << endl; ` ` ` ` ` `return` `0; ` `} ` |

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## Java

`// Java Program to find the biggest cube ` `// inscribed within a right circular cylinder ` `class` `Solution ` `{ ` ` ` ` ` `// Function to find the volume of the cube ` `static` `float` `cube(` `float` `h, ` `float` `r) ` `{ ` ` ` ` ` `// height and radius cannot be negative ` ` ` `if` `(h < ` `0` `&& r < ` `0` `) ` ` ` `return` `-` `1` `; ` ` ` ` ` `// volume of the cube ` ` ` `float` `a = (` `float` `)Math.pow(h, ` `3` `); ` ` ` ` ` `return` `a; ` `} ` ` ` `// Driver code ` `public` `static` `void` `main(String args[]) ` `{ ` ` ` `float` `h = ` `5` `, r = ` `4` `; ` ` ` `System.out.println( cube(h, r) ); ` `} ` `} ` `//contributed by Arnab Kundu ` |

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## Python 3

# Python 3 Program to find the biggest cube

# inscribed within a right circular cylinder

import math

# Function to find the volume of the cube

def cube(h, r):

# height and radius cannot be negative

if (h < 0 and r < 0):
return -1
# volume of the cube
a = math.pow(h, 3)
return a
# Driver code
h = 5; r = 4;
print(cube(h, r));
# This code is contributed
# by Akanksha Rai
[tabby title="C#"]

`// C# Program to find the biggest ` `// cube inscribed within a right ` `// circular cylinder ` `using` `System; ` ` ` `class` `GFG ` `{ ` ` ` `// Function to find the volume ` `// of the cube ` `static` `float` `cube(` `float` `h, ` `float` `r) ` `{ ` ` ` ` ` `// height and radius cannot ` ` ` `// be negative ` ` ` `if` `(h < 0 && r < 0) ` ` ` `return` `-1; ` ` ` ` ` `// volume of the cube ` ` ` `float` `a = (` `float` `)Math.Pow(h, 3); ` ` ` ` ` `return` `a; ` `} ` ` ` `// Driver code ` `public` `static` `void` `Main() ` `{ ` ` ` `float` `h = 5, r = 4; ` ` ` `Console.Write( cube(h, r) ); ` `} ` `} ` ` ` `// This code is contributed ` `// by 29AjayKumar ` |

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## PHP

`<?php ` `// PHP Program to find the biggest ` `// cube inscribed within a right ` `// circular cylinder ` ` ` `// Function to find the volume ` `// of the cube ` `function` `cube(` `$h` `, ` `$r` `) ` `{ ` ` ` ` ` `// height and radius cannot ` ` ` `// be negative ` ` ` `if` `(` `$h` `< 0 && ` `$r` `< 0) ` ` ` `return` `-1; ` ` ` ` ` `// volume of the cube ` ` ` `$a` `= pow(` `$h` `, 3); ` ` ` ` ` `return` `$a` `; ` `} ` ` ` `// Driver code ` `$h` `= 5; ` `$r` `= 4; ` `echo` `cube(` `$h` `, ` `$r` `); ` ` ` `// This code is contributed by @Tushil. ` `?> ` |

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**Output:**

125

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