k-th missing element in sorted array

Given an increasing sequence a[], we need to find the K-th missing contiguous element in the increasing sequence which is not present in the sequence. If no k-th missing element is there output -1.

Examples :

Input : a[] = {2, 3, 5, 9, 10};   
        k = 1;
Output : 4
Explanation: Missing Element in the increasing 
sequence are {4, 6, 7, 8}. So k-th missing element
is 4

Input : a[] = {2, 3, 5, 9, 10, 11, 12};       
        k = 4;
Output : 8
Explanation: missing element in the increasing 
sequence are {4, 6, 7, 8}  so k-th missing 
element is 8

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Start iterating over the array elements, and for every element check if next element is consecutive or not, if not, then take difference between these two, and check if difference is greater than or equal to given k, then calculate ans = a[i] + count, else iterate for next element.

C++

#include <bits/stdc++.h> 
using namespace std; 
  
// Function to find k-th  
// missing element 
int missingK(int a[], int k,  
             int n) 
{ 
    int difference = 0,  
        ans = 0, count = k; 
    bool flag = 0; 
      
    // interating over the array 
    for(int i = 0 ; i < n - 1; i++) 
    {    
        difference = 0; 
          
        // check if i-th and  
        // (i + 1)-th element  
        // are not consecutive 
        if ((a[i] + 1) != a[i + 1])  
        { 
              
            // save their difference 
            difference +=  
                (a[i + 1] - a[i]) - 1; 
              
            // check for difference 
            // and given k 
            if (difference >= count) 
                { 
                    ans = a[i] + count; 
                    flag = 1; 
                    break; 
                } 
            else
                count -= difference; 
        } 
    } 
      
    // if found 
    if(flag) 
        return ans; 
    else
        return  -1; 
} 
  
// Driver code 
int main() 
{ 
    // Input array 
    int a[] = {1, 5, 11, 19}; 
      
    // k-th missing element  
    // to be found in the array 
    int k = 11; 
    int n = sizeof(a) / sizeof(a[0]); 
      
    // calling function to 
    // find missing element 
    int missing = missingK(a, k, n); 
      
    cout << missing << endl; 
      
    return 0; 
} 

Java

// Java program to check for 
// even or odd 
import java.io.*; 
import java.util.*; 
   
public class GFG { 
       
    // Function to find k-th  
    // missing element 
    static int missingK(int []a, int k,  
                                 int n) 
    { 
        int difference = 0,  
            ans = 0, count = k; 
        boolean flag = false; 
           
        // interating over the array 
        for(int i = 0 ; i < n - 1; i++) 
        {  
            difference = 0; 
               
            // check if i-th and  
            // (i + 1)-th element  
            // are not consecutive 
            if ((a[i] + 1) != a[i + 1])  
            { 
                   
                // save their difference 
                difference +=  
                    (a[i + 1] - a[i]) - 1; 
                   
                // check for difference 
                // and given k 
                if (difference >= count) 
                    { 
                        ans = a[i] + count; 
                        flag = true; 
                        break; 
                    } 
                else
                    count -= difference; 
            } 
        } 
           
        // if found 
        if(flag) 
            return ans; 
        else
            return -1; 
    } 
       
    // Driver code 
    public static void main(String args[]) 
    { 
           
        // Input array 
        int []a = {1, 5, 11, 19}; 
           
        // k-th missing element  
        // to be found in the array 
        int k = 11; 
        int n = a.length; 
           
        // calling function to 
        // find missing element 
        int missing = missingK(a, k, n); 
           
        System.out.print(missing); 
    } 
   
} 
   
// This code is contributed by 
// Manish Shaw (manishshaw1) 

Python3

# Function to find k-th  
# missing element 
def missingK(a, k, n) : 
  
    difference = 0
    ans = 0
    count = k 
    flag = 0
      
    # interating over the array 
    for i in range (0, n-1) :  
        difference = 0
          
        # check if i-th and  
        # (i + 1)-th element  
        # are not consecutive 
        if ((a[i] + 1) != a[i + 1]) : 
          
              
            # save their difference 
            difference += (a[i + 1] - a[i]) - 1
              
            # check for difference 
            # and given k 
            if (difference >= count) : 
                    ans = a[i] + count 
                    flag = 1
                    break
            else : 
                count -= difference      
      
    # if found 
    if(flag) : 
        return ans 
    else : 
        return -1
  
# Driver code 
# Input array 
a = [1, 5, 11, 19] 
  
# k-th missing element  
# to be found in the array 
k = 11
n = len(a) 
  
# calling function to 
# find missing element 
missing = missingK(a, k, n) 
  
print(missing) 
  
# This code is contributed by  
# Manish Shaw (manishshaw1) 

C#

// C# program to check for 
// even or odd 
using System; 
using System.Collections.Generic; 
  
class GFG { 
      
    // Function to find k-th  
    // missing element 
    static int missingK(int []a, int k,  
                                 int n) 
    { 
        int difference = 0,  
            ans = 0, count = k; 
        bool flag = false; 
          
        // interating over the array 
        for(int i = 0 ; i < n - 1; i++) 
        {  
            difference = 0; 
              
            // check if i-th and  
            // (i + 1)-th element  
            // are not consecutive 
            if ((a[i] + 1) != a[i + 1])  
            { 
                  
                // save their difference 
                difference +=  
                    (a[i + 1] - a[i]) - 1; 
                  
                // check for difference 
                // and given k 
                if (difference >= count) 
                    { 
                        ans = a[i] + count; 
                        flag = true; 
                        break; 
                    } 
                else
                    count -= difference; 
            } 
        } 
          
        // if found 
        if(flag) 
            return ans; 
        else
            return -1; 
    } 
      
    // Driver code 
    public static void Main() 
    { 
          
        // Input array 
        int []a = {1, 5, 11, 19}; 
          
        // k-th missing element  
        // to be found in the array 
        int k = 11; 
        int n = a.Length; 
          
        // calling function to 
        // find missing element 
        int missing = missingK(a, k, n); 
          
        Console.Write(missing); 
    } 
  
} 
  
// This code is contributed by 
// Manish Shaw (manishshaw1) 

PHP

<?php 
// Function to find k-th  
// missing element 
function missingK(&$a, $k, $n) 
{ 
    $difference = 0; 
    $ans = 0; 
    $count = $k; 
    $flag = 0; 
      
    // interating over the array 
    for($i = 0 ; $i < $n - 1; $i++) 
    {  
        $difference = 0; 
          
        // check if i-th and  
        // (i + 1)-th element  
        // are not consecutive 
        if (($a[$i] + 1) != $a[$i + 1])  
        { 
              
            // save their difference 
            $difference += ($a[$i + 1] -  
                            $a[$i]) - 1; 
              
            // check for difference 
            // and given k 
            if ($difference >= $count) 
                { 
                    $ans = $a[$i] + $count; 
                    $flag = 1; 
                    break; 
                } 
            else
                $count -= $difference; 
        } 
    } 
      
    // if found 
    if($flag) 
        return $ans; 
    else
        return -1; 
} 
  
// Driver Code 
  
// Input array 
$a = array(1, 5, 11, 19); 
  
// k-th missing element  
// to be found in the array 
$k = 11; 
$n = count($a); 
  
// calling function to 
// find missing element 
$missing = missingK($a, $k, $n); 
  
echo $missing; 
  
// This code is contributed by Manish Shaw 
// (manishshaw1) 
?> 

Output :

Time Complexity :O(n), where n is the number of elements in the array.

My Personal Notes

Suggest a Topic

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

C++

Java

Python3

C#

PHP

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