Given an integer k and a string str consisting of lowercase English alphabets, the task is to count how many k character words (with or without meaning) can be formed from the characters of str when repetition is not allowed.
Input: str = “cat”, k = 3
Required words are “cat”, “cta”, “act”, “atc”, “tca” and “tac”.
Input: str = “geeksforgeeks”, k = 3
Approach: Count the number of distinct characters in str and store it in cnt, now the task is to arrange k characters out of cnt characters i.e. nPr = n! / (n – r)!.
Below is the implementation of the above approach:
- Print all possible strings of length k that can be formed from a set of n characters
- Check if the given string of words can be formed from words present in the dictionary
- Print all permutations with repetition of characters
- Convert to a string that is repetition of a substring of k length
- Minimum length of the sub-string whose characters can be used to form a palindrome of length K
- Group words with same set of characters
- Possible Words using given characters in Python
- Dyck Words of given length
- Print all valid words that are possible using Characters of Array
- Python | Toggle characters in words having same case
- Find words which are greater than given length k
- Generating Lyndon words of length n
- Java program to swap first and last characters of words in a sentence
- LCS formed by consecutive segments of at least length K
- All possible strings of any length that can be formed from a given string
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