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jQuery UI Buttonset widget() Method

Last Updated : 10 Jan, 2022
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jQuery UI consists of GUI widgets, visual effects, and themes implemented using HTML, CSS, and jQuery. jQuery UI is great for building UI interfaces for the webpages. The jQuery UI Buttonset widget is used to give a visual grouping for a group of related buttons.

The jQuery UI buttonset widget() method is used for returning a jQuery buttons object.

Syntax:

var widget = $( ".selector" ).buttonset( "widget" );

Parameters: This method does not accept any parameter.

Return values: This method does not return any values.

CDN Link: First, add jQuery UI scripts needed for your project.

<link rel=”stylesheet” href=”//code.jquery.com/ui/1.12.1/themes/smoothness/jquery-ui.css”>
<script src=”//code.jquery.com/jquery-1.12.4.js”></script>
<script src=”//code.jquery.com/ui/1.12.1/jquery-ui.js”></script>

Example: This example demonstrates the jQuery UI buttonset widget() Method.

HTML




<!doctype html>
<html lang="en">
  
<head>
    <meta charset="utf-8">
    <link rel="stylesheet" href=
"//code.jquery.com/ui/1.12.1/themes/smoothness/jquery-ui.css">
    <script src=
"//code.jquery.com/jquery-1.12.4.js">
    </script>
    <script src=
"//code.jquery.com/ui/1.12.1/jquery-ui.js">
    </script>
</head>
  
<body>
    <center>
        <h1 style="color:green;">
            GeeksforGeeks
        </h1>
        <h3>jQuery UI Buttonset widget() Method</h3>
        <form>
            <fieldset>
                <legend>Button_Set</legend>
                <div id="ButtonSet_Radio">
                    <input id="Company" type="radio" 
                           checked="checked">
                    <label for="Company">GeeksforGeeks</label>
                    <input id="Department" type="radio">
                    <label for="Department">Computer Science</label>
                </div>
            </fieldset>
        </form>
        <input type="button" id="Button_for_widget" 
               style="padding:5px 15px; margin-top:40px;"
               value="Get the buttons object">
        <div id="log"></div>
    </center>
    <script>
        $(document).ready(function () {
            $("#ButtonSet_Radio").buttonset();
            $("#Button_for_widget").on('click', function () {
                var a = $("#ButtonSet_Radio").buttonset("widget");
                $("#log").html(a);
            });
        });
    </script>
</body>
  
</html>


Output:

jQuery UI Buttonset widget() Method

Reference: https://api.jqueryui.com/buttonset/#method-widget



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