JavaScript program to print even numbers in an array
Given an array of numbers and the task is to write a JavaScript program to print all even numbers in that array.
We will use the following methods to find even numbers in an array:
Example:
Input: numbers_array1= [4, 76, 89, 61, 72, 64]
Output: [4,76,72,64]
Input: numbers_array2= [15, 60, 90, 14, 7, 45]
Output: [60,90,14]
- Iterate each element in the array using for loop to check if (num %2==0), the condition to check even or not.
- If the condition is satisfied then push the num into the even list.
- After iterating all elements in an array print the even list.
Example: In this example, we are Using for Loop
Javascript
let numbers = [10, 23, 12, 21];
let even = [];
for (let i = 0; i < numbers.length; i++) {
if (numbers[i] % 2 == 0)
even.push(numbers[i]);
}
console.log(`Even numbers in an array are: ${even}`);
|
Output
Even numbers in an array are: 10,12
- Iterate through the array using the while loop.
- Check elements if (element%2==0) condition satisfies, we push the element into an even array.
- After iterating all elements using a while loop, we print an even numbers array.
Example: In this example, we are Using while Loop
Javascript
let numbers=[44, 26, 48, 64, 27, 53];
let even = [];
let i = 0;
while (i < numbers.length) {
if (numbers[i] % 2 == 0)
even.push(numbers[i]);
i++;
}
console.log(`Even numbers in an array are: ${even}`)
|
Output
Even numbers in an array are: 44,26,48,64
- Declare an array called “numbers” containing a set of integers.
- Declare an empty array called “even”.
- Use the forEach method to iterate through each element in the “numbers” array.
- Within the forEach loop, use an if statement to check if the current element is even using the modulus operator (element%2==0).
- If the element is even, use the push method to add it to the “even” array.
- After the forEach loop, use console.log () to display the message “Even numbers in an array are: [even numbers]” where [even numbers] is the array of even numbers.
This approach allows one to iterate through the entire array, check each element for even-ness, and add even numbers to a separate array, which is then displayed in the console.
Example: In this example, we are Using forEach Loop
Javascript
let numbers = [86, 41, 55, 85, 90, 24];
let even = [];
numbers.forEach(element => {
if ( element%2 == 0 )
even.push(element);
});
console.log(`Even numbers in an array are: ${even}`);
|
Output
Even numbers in an array are: 86,90,24
- Declare an array called “numbers” containing a set of integers.
- Use the filter() method on the “numbers” array, passing in a callback function as the argument.
- The callback function should take in the current element as a parameter and use the modulus operator (element%2==0) to check if it is even.
- Return true for even numbers and false for odd numbers in the callback function.
- Assign the returned result of the filter method to a variable, let’s say ‘evenNumbers’.
- After the filter method, use console.log() to display the message “Even numbers in an array are: [evenNumbers]” where [evenNumbers] is the array of even numbers returned from the filter method.
The filter method returns a new array with all elements that pass the test implemented by the callback function.
Example: In this example, we are Using filter Method
Javascript
let numbers = [86, 41, 55, 85, 90, 24];
let evenNumbers = numbers.filter( function (element) {
return element % 2 === 0;
});
console.log(`Even numbers in an array are: ${evenNumbers}`);
|
Output
Even numbers in an array are: 86,90,24
The for…of loop iterates over the iterable objects (like Array, Map, Set, arguments object, …,etc), invoking a custom iteration hook with statements to be executed for the value of each distinct property.
Example: In this example, we are Using for…of Loop
Javascript
const even = [];
const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];
for (const num of arr) {
if (num % 2 === 0) {
even.push(num);
}
}
console.log(even);
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Last Updated :
22 Dec, 2023
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