Javascript Program to Modify a matrix by rotating ith row exactly i times in clockwise direction
Given a matrix mat[][] of dimensions M * N, the task is to print the matrix obtained after rotating every ith row of the matrix i times in a clockwise direction.
Examples:
Input: mat[][] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}
Output:
1 2 3
6 4 5
8 9 7
Explanation:
The 0th row is rotated 0 times. Therefore, the 0th row remains the same as {1, 2, 3}.
The 1st row is rotated 1 times. Therefore, the 1st row modifies to {6, 4, 5}.
The 2nd row is rotated 2 times. Therefore, the 2nd row modifies to {8, 9, 7}.
After completing the above operations, the given matrix modifies to {{1, 2, 3}, {6, 4, 5}, {8, 9, 7}}.
Input: mat[][] = {{1, 2, 3, 4}, {4, 5, 6, 7}, {7, 8, 9, 8}, {7, 8, 9, 8}}
Output:
1 2 3 4
7 4 5 6
9 8 7 8
8 9 8 7
Approach: Follow the steps below to solve the problem:
Below is the implementation of the above approach:
Javascript
<script>
function reverse(arr,start,end)
{
while (start < end) {
let temp = arr[start];
arr[start] = arr[end];
arr[end] = temp;
start++;
end--;
}
}
function rotateMatrix(mat)
{
let i = 0;
for (let rows=0;rows<mat.length;rows++) {
reverse(mat[rows], 0, mat[rows].length - 1);
reverse(mat[rows], 0, i - 1);
reverse(mat[rows], i, mat[rows].length - 1);
i++;
}
for (let rows=0;rows< mat.length;rows++) {
for (let cols=0;cols< mat[rows].length;cols++) {
document.write(mat[rows][cols] + " " );
}
document.write( "<br>" );
}
}
let mat=[[ 1, 2, 3 ],
[ 4, 5, 6 ],
[ 7, 8, 9 ]];
rotateMatrix(mat);
</script>
|
Output:
1 2 3
6 4 5
8 9 7
Time Complexity: O(N*M), as we are using nested loops to traverse N*M times.
Auxiliary Space: O(1), as we are not using any extra space.
Please refer complete article on Modify a matrix by rotating ith row exactly i times in clockwise direction for more details!
Last Updated :
30 May, 2022
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