Javascript Program For Recursive Selection Sort For Singly Linked List – Swapping Node Links
Given a singly linked list containing n nodes. The problem is to sort the list using the recursive selection sort technique. The approach should be such that it involves swapping node links instead of swapping node data.
Examples:
Input: 10 -> 12 -> 8 -> 4 -> 6 Output: 4 -> 6 -> 8 -> 10 -> 12
In Selection Sort, we first find the minimum element, swap it with the beginning node and recur for the remaining list. Below is the recursive implementation of these steps for the linked list.
recurSelectionSort(head) if head->next == NULL return head Initialize min = head Initialize beforeMin = NULL Initialize ptr = head while ptr->next != NULL if min->data > ptr->next->data min = ptr->next beforeMin = ptr ptr = ptr->next if min != head swapNodes(&head, head, min, beforeMin) head->next = recurSelectionSort(head->next) return head swapNodes(head_ref, currX, currY, prevY) head_ref = currY prevY->next = currX Initialize temp = currY->next currY->next = currX->next currX->next = temp
The swapNodes(head_ref, currX, currY, prevY) is based on the approach discussed here but it has been modified accordingly for the implementation of this post.
Javascript
<script> // Javascript implementation of recursive // selection sort for singly linked list // | Swapping node links // A Linked list node class Node { constructor(val) { this .data = val; this .next = null ; } } // Function to swap nodes 'currX' and // 'currY' in a linked list without // swapping data function swapNodes(head_ref, currX, currY, prevY) { // Make 'currY' as new head head_ref = currY; // Adjust links prevY.next = currX; // Swap next pointers var temp = currY.next; currY.next = currX.next; currX.next = temp; return head_ref; } // Function to sort the linked list using // recursive selection sort technique function recurSelectionSort(head) { // If there is only a single node if (head.next == null ) return head; // 'min' - pointer to store the node // having minimum data value var min = head; // 'beforeMin' - pointer to store node // previous to 'min' node var beforeMin = null ; var ptr; // Traverse the list till the last node for (ptr = head; ptr.next != null ; ptr = ptr.next) { // if true, then update 'min' and // 'beforeMin' if (ptr.next.data < min.data) { min = ptr.next; beforeMin = ptr; } } // if 'min' and 'head' are not same, // swap the head node with the 'min' node if (min != head) head = swapNodes(head, head, min, beforeMin); // recursively sort the remaining list head.next = recurSelectionSort(head.next); return head; } // Function to sort the given linked list function sort(head_ref) { // If list is empty if ((head_ref) == null ) return null ; // Sort the list using recursive // selection sort technique head_ref = recurSelectionSort(head_ref); return head_ref; } // Function to insert a node at the // beginning of the linked list function push(head_ref, new_data) { // Allocate node var new_node = new Node(); // Put in the data new_node.data = new_data; // Link the old list to the // new node new_node.next = (head_ref); // Move the head to point to the // new node (head_ref) = new_node; return head_ref; } // Function to print the linked list function printList(head) { while (head != null ) { document.write(head.data + " " ); head = head.next; } } // Driver code var head = null ; // Create linked list 10.12.8.4.6 head = push(head, 6); head = push(head, 4); head = push(head, 8); head = push(head, 12); head = push(head, 10); document.write( "Linked list before sorting:<br/>" ); printList(head); // Sort the linked list head = sort(head); document.write( "<br/>Linked list after sorting:<br/>" ); printList(head); // This code is contributed by todaysgaurav </script> |
Output:
Linked list before sorting: 10 12 8 4 6 Linked list after sorting: 4 6 8 10 12
Time Complexity: O(n2)
Auxiliary Space: O(n)
Please refer complete article on Recursive selection sort for singly linked list | Swapping node links for more details!
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