Javascript Program for Least frequent element in an array
Given an array, find the least frequent element in it. If there are multiple elements that appear least number of times, print any one of them.
Examples :Â
Â
Input : arr[] = {1, 3, 2, 1, 2, 2, 3, 1}
Output : 3
3 appears minimum number of times in given
array.
Input : arr[] = {10, 20, 30}
Output : 10 or 20 or 30
Â
A simple solution is to run two loops. The outer loop picks all elements one by one. The inner loop finds frequency of the picked element and compares with the minimum so far. Time complexity of this solution is O(n2)
A better solution is to do sorting. We first sort the array, then linearly traverse the array.
Â
Javascript
<script>
function leastFrequent(arr, n)
{
arr.sort();
let min_count = n+1, res = -1;
let curr_count = 1;
for (let i = 1; i < n; i++) {
if (arr[i] == arr[i - 1])
curr_count++;
else {
if (curr_count < min_count) {
min_count = curr_count;
res = arr[i - 1];
}
curr_count = 1;
}
}
if (curr_count < min_count)
{
min_count = curr_count;
res = arr[n - 1];
}
return res;
}
let arr = [1, 3, 2, 1, 2, 2, 3, 1];
let n = arr.length;
document.write(leastFrequent(arr, n));
</script>
|
Time Complexity : O(n Log n)Â
Auxiliary Space : O(1)
An efficient solution is to use hashing. We create a hash table and store elements and their frequency counts as key value pairs. Finally we traverse the hash table and print the key with minimum value.
Â
Javascript
<script>
function leastFrequent(arr, n)
{
var hash = new Map();
for ( var i = 0; i < n; i++)
{
if (hash.has(arr[i]))
hash.set(arr[i], hash.get(arr[i])+1)
else
hash.set(arr[i], 1);
}
var min_count = n+1, res = -1;
hash.forEach((value, key) => {
if (min_count >= value) {
res = key;
min_count = value;
}
});
return res;
}
var arr = [1, 3, 2, 1, 2, 2, 3, 1];
var n = arr.length;
document.write( leastFrequent(arr, n));
</script>
|
Time Complexity : O(n)Â
Auxiliary Space : O(n)
Â
Please refer complete article on Least frequent element in an array for more details!
Last Updated :
19 Jan, 2022
Like Article
Save Article
Share your thoughts in the comments
Please Login to comment...