Javascript Program for Frequencies of even and odd numbers in a matrix
Given a matrix of order m*n then the task is to find the frequency of even and odd numbers in matrix
Examples:
Input : m = 3, n = 3
{ 1, 2, 3 },
{ 4, 5, 6 },
{ 7, 8, 9 }
Output : Frequency of odd number = 5
Frequency of even number = 4
Input : m = 3, n = 3
{ 10, 11, 12 },
{ 13, 14, 15 },
{ 16, 17, 18 }
Output : Frequency of odd number = 4
Frequency of even number = 5
Javascript
<script>
let MAX = 100;
function freq(ar,m,n) {
let even = 0, odd = 0;
for (let i = 0; i < m; ++i)
{
for (let j = 0; j < n; ++j)
{
if ((ar[i][j] % 2) == 0)
++even;
else
++odd;
}
}
document.write( " Frequency of odd number =" +
odd + " <br>" );
document.write( " Frequency of even number = " +
even + "<br>" );
}
let m = 3, n = 3;
let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]];
freq(array, m, n);
</script>
|
Output:
Frequency of odd number = 5
Frequency of even number = 4
Time Complexity: O(m*n)
Auxiliary Space: O(1)
Method: Using bitwise & operator
Javascript
<script>
let MAX = 100;
function freq(ar,m,n) {
let even = 0, odd = 0;
for (let i = 0; i < m; ++i)
{
for (let j = 0; j < n; ++j)
{
if ((ar[i][j]&1) == 0)
++even;
else
++odd;
}
}
document.write( " Frequency of odd number =" +
odd + " <br>" );
document.write( " Frequency of even number = " +
even + "<br>" );
}
let m = 3, n = 3;
let array = [[1, 2, 3], [4, 5, 6], [7, 8, 9]];
freq(array, m, n);
</script>
|
Output:
Frequency of odd number = 5
Frequency of even number = 4
Time Complexity: O(m*n)
Auxiliary Space: O(1)
Please refer complete article on Frequencies of even and odd numbers in a matrix for more details!
Last Updated :
18 Jan, 2023
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