Javascript Program For Deleting A Linked List Node At A Given Position
Last Updated :
15 Jun, 2022
Given a singly linked list and a position, delete a linked list node at the given position.
Example:
Input: position = 1, Linked List = 8->2->3->1->7
Output: Linked List = 8->3->1->7
Input: position = 0, Linked List = 8->2->3->1->7
Output: Linked List = 2->3->1->7
If the node to be deleted is the root, simply delete it. To delete a middle node, we must have a pointer to the node previous to the node to be deleted. So if positions are not zero, we run a loop position-1 times and get a pointer to the previous node.
Below is the implementation of the above idea.
Javascript
<script>
var head;
class Node
{
constructor(val)
{
this .data = val;
this .next = null ;
}
}
function push(new_data)
{
var new_node = new Node(new_data);
new_node.next = head;
head = new_node;
}
function deleteNode(position)
{
if (head == null )
return ;
var temp = head;
if (position == 0)
{
head = temp.next;
return ;
}
for (i = 0; temp != null && i < position - 1; i++)
temp = temp.next;
if (temp == null || temp.next == null )
return ;
var next = temp.next.next;
temp.next = next;
}
function printList()
{
var tnode = head;
while (tnode != null )
{
document.write(tnode.data + " " );
tnode = tnode.next;
}
}
push(7);
push(1);
push(3);
push(2);
push(8);
document.write( "Created Linked list is: <br/>" );
printList();
deleteNode(4);
document.write( "<br/>Linked List after " +
"Deletion at position 4: <br/>" );
printList();
</script>
|
Output:
Created Linked List:
8 2 3 1 7
Linked List after Deletion at position 4:
8 2 3 1
Time Complexity: O(n), where n represents the length of the given linked list.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Please refer complete article on Delete a Linked List node at a given position for more details!
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