Java Program to Print uncommon elements from two sorted arrays

Given two sorted arrays of distinct elements, we need to print those elements from both arrays that are not common. The output should be printed in sorted order. 
Examples :

Input : arr1[] = {10, 20, 30}
        arr2[] = {20, 25, 30, 40, 50}
Output : 10 25 40 50
We do not print 20 and 30 as these
elements are present in both arrays.

Input : arr1[] = {10, 20, 30}
        arr2[] = {40, 50}
Output : 10 20 30 40 50
        

The idea is based on merge process of merge sort. We traverse both arrays and skip common elements.

Java

// Java program to find uncommon elements
// of two sorted arrays
import java.io.*;

class GFG {

    static void printUncommon(int arr1[],
                     int arr2[], int n1, int n2)
    {

        int i = 0, j = 0, k = 0;
        while (i < n1 && j < n2) {

            // If not common, print smaller
            if (arr1[i] < arr2[j]) {
                System.out.print(arr1[i] + " ");
                i++;
                k++;
            }
            else if (arr2[j] < arr1[i]) {
                System.out.print(arr2[j] + " ");
                k++;
                j++;
            }

            // Skip common element
            else {
                i++;
                j++;
            }
        }

        // printing remaining elements
        while (i < n1) {
            System.out.print(arr1[i] + " ");
            i++;
            k++;
        }
        while (j < n2) {
            System.out.print(arr2[j] + " ");
            j++;
            k++;
        }
    }

    // Driver code
    public static void main(String[] args)
    {
        int arr1[] = { 10, 20, 30 };
        int arr2[] = { 20, 25, 30, 40, 50 };

        int n1 = arr1.length;
        int n2 = arr2.length;

        printUncommon(arr1, arr2, n1, n2);
    }
}

// This code is contributed by vt_m

Output :

10 25 40 50

Time Complexity: O(n1 + n2), where n1 and n2 represents the size of the given two arrays.
Auxiliary Space: O(1), no extra space is required, so it is a constant.

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