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# Java Program to Move all zeroes to end of array | Set-2 (Using single traversal)

Given an array of n numbers. The problem is to move all the 0’s to the end of the array while maintaining the order of the other elements. Only single traversal of the array is required.
Examples:

```Input : arr[]  = {1, 2, 0, 0, 0, 3, 6}
Output : 1 2 3 6 0 0 0

Input: arr[] = {0, 1, 9, 8, 4, 0, 0, 2, 7, 0, 6, 0, 9}
Output: 1 9 8 4 2 7 6 9 0 0 0 0 0```

Algorithm:

```moveZerosToEnd(arr, n)
Initialize count = 0
for i = 0 to n-1
if (arr[i] != 0) then
swap(arr[count++], arr[i])```

## Java

 `// Java implementation to move ``// all zeroes at the end of array``import` `java.io.*;`` ` `class` `GFG {`` ` `// function to move all zeroes at``// the end of array``static` `void` `moveZerosToEnd(``int` `arr[], ``int` `n) {``     ` `    ``// Count of non-zero elements``    ``int` `count = ``0``;``    ``int` `temp;`` ` `    ``// Traverse the array. If arr[i] is ``    ``// non-zero, then swap the element at ``    ``// index 'count' with the element at ``    ``// index 'i'``    ``for` `(``int` `i = ``0``; i < n; i++) {``    ``if` `((arr[i] != ``0``)) {``        ``temp = arr[count];``        ``arr[count] = arr[i];``        ``arr[i] = temp;``        ``count = count + ``1``;``    ``}``    ``}``}`` ` `// function to print the array elements``static` `void` `printArray(``int` `arr[], ``int` `n) {``    ``for` `(``int` `i = ``0``; i < n; i++)``    ``System.out.print(arr[i] + ``" "``);``}`` ` `// Driver program to test above``public` `static` `void` `main(String args[]) {``    ``int` `arr[] = {``0``, ``1``, ``9``, ``8``, ``4``, ``0``, ``0``, ``2``,``                         ``7``, ``0``, ``6``, ``0``, ``9``};``    ``int` `n = arr.length;`` ` `    ``System.out.print(``"Original array: "``);``    ``printArray(arr, n);`` ` `    ``moveZerosToEnd(arr, n);`` ` `    ``System.out.print("``Modified array: ");``    ``printArray(arr, n);``}``}`` ` `// This code is contributed by Nikita Tiwari.`

Output:

```Original array: 0 1 9 8 4 0 0 2 7 0 6 0 9
Modified array: 1 9 8 4 2 7 6 9 0 0 0 0 0```

Time Complexity: O(n).
Auxiliary Space: O(1).

Please refer complete article on Move all zeroes to end of array | Set-2 (Using single traversal) for more details!

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