Java Program to find transpose of a matrix
Transpose of a matrix is obtained by changing rows to columns and columns to rows. In other words, transpose of A[][] is obtained by changing A[i][j] to A[j][i].
For Square Matrix :
The below program finds transpose of A[][] and stores the result in B[][], we can change N for different dimension.
// Java Program to find // transpose of a matrix class GFG{ static final int N = 4; // This function stores transpose // of A[][] in B[][] static void transpose(int A[][], int B[][]) { int i, j; for (i = 0; i < N; i++) for (j = 0; j < N; j++) B[i][j] = A[j][i]; } // Driver code public static void main (String[] args) { int A[][] = { {1, 1, 1, 1}, {2, 2, 2, 2}, {3, 3, 3, 3}, {4, 4, 4, 4}}; int B[][] = new int[N][N], i, j; transpose(A, B); System.out.print("Result matrix is \n"); for (i = 0; i < N; i++) { for (j = 0; j < N; j++) System.out.print(B[i][j] + " "); System.out.print("\n"); } }} // This code is contributed by Anant Agarwal. |
Output:
Result matrix is 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4
For Rectangular Matrix :
The below program finds transpose of A[][] and stores the result in B[][].
// Java Program to find // transpose of a matrix class GFG{ static final int M = 3; static final int N = 4; // This function stores transpose // of A[][] in B[][] static void transpose(int A[][], int B[][]) { int i, j; for (i = 0; i < N; i++) for (j = 0; j < M; j++) B[i][j] = A[j][i]; } // Driver code public static void main (String[] args) { int A[][] = { {1, 1, 1, 1}, {2, 2, 2, 2}, {3, 3, 3, 3}}; int B[][] = new int[N][M], i, j; transpose(A, B); System.out.print("Result matrix is \n"); for (i = 0; i < N; i++) { for (j = 0; j < M; j++) System.out.print(B[i][j] + " "); System.out.print("\n"); } }} // This code is contributed by Anant Agarwal. |
Output:
Result matrix is 1 2 3 1 2 3 1 2 3 1 2 3
In-Place for Square Matrix:
// Java Program to find // transpose of a matrix class GFG{ static final int N = 4; // Finds transpose of A[][] in-place static void transpose(int A[][]) { for (int i = 0; i < N; i++) for (int j = i+1; j < N; j++) { int temp = A[i][j]; A[i][j] = A[j][i]; A[j][i] = temp; } } // Driver code public static void main (String[] args) { int A[][] = { {1, 1, 1, 1}, {2, 2, 2, 2}, {3, 3, 3, 3}, {4, 4, 4, 4}}; transpose(A); System.out.print("Modified matrix is \n"); for (int i = 0; i < N; i++) { for (int j = 0; j < N; j++) System.out.print(A[i][j] + " "); System.out.print("\n"); } }} |
Output:
Modified matrix is 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4
Please refer complete article on Program to find transpose of a matrix for more details!
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