Java Program to Find maximum element of each row in a matrix

Given a matrix, the task is to find the maximum element of each row.

Examples:

Input :  [1, 2, 3]
         [1, 4, 9]
         [76, 34, 21]

Output :
3
9
76

Input : [1, 2, 3, 21]
        [12, 1, 65, 9]
        [1, 56, 34, 2]
Output :
21
65
56

Approach : Approach is very simple. The idea is to run the loop for no_of_rows. Check each element inside the row and find for the maximum element. Finally, print the element. 

Below is the implementation : 

Java

// Java program to find maximum
// element of each row in a matrix
public class GFG{

    // Function to get max element
    public static void maxelement(int no_of_rows, int[][] arr) {
        int i = 0;

        // Initialize max to 0 at beginning
        // of finding max element of each row
        int max = 0;
        int[] result = new int[no_of_rows];
        while (i < no_of_rows) {
            for (int j = 0; j < arr[i].length; j++) {
                if (arr[i][j] > max) {
                    max = arr[i][j];
                }
            }
            result[i] = max;
            max =0;
            i++;

        }
        printArray(result);

    }

    // Print array element
    private static void printArray(int[] result) {
        for (int i =0; i<result.length;i++) {
            System.out.println(result[i]);
        }

    }

    // Driver code
    public static void main(String[] args) {
        int[][] arr = new int[][] { {3, 4, 1, 8},
                                    {1, 4, 9, 11},
                                    {76, 34, 21, 1},
                                   {2, 1, 4, 5} };
       // Calling the function
        maxelement(4, arr);
    }
}

Output

8
11
76
5

Time Complexity: O(R*C) where R and C are numbers of rows and columns of a given matrix respectively.
Auxiliary Space: O(R), extra space for array result[]

Please refer complete article on Find maximum element of each row in a matrix for more details!