Integers X and K are given. The task is to find the smallest K-digit number divisible by X.
Input : X = 83, K = 5 Output : 10043 10040 is the smallest 5 digit number that is multiple of 83. Input : X = 5, K = 2 Output : 10
An efficient solution would be :
Compute MIN : smallest K-digit number (1000...K-times) If, MIN % X is 0, ans = MIN else, ans = (MIN + X) - ((MIN + X) % X)) This is because there will be a number in range [MIN...MIN+X] divisible by X.
To understand Math.pow() function, please refer point 18 of the article :
Please refer complete article on Smallest K digit number divisible by X for more details!
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