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Java Program for Sieve of Eratosthenes

  • Difficulty Level : Easy
  • Last Updated : 05 May, 2021
Geek Week

Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number. 
For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”.  
 

Java




// Java program to print all primes smaller than or equal to
// n using Sieve of Eratosthenes
 
class SieveOfEratosthenes
{
    void sieveOfEratosthenes(int n)
    {
        // Create a boolean array "prime[0..n]" and initialize
        // all entries it as true. A value in prime[i] will
        // finally be false if i is Not a prime, else true.
        boolean prime[] = new boolean[n+1];
        for(int i=0;i<=n;i++)
            prime[i] = true;
         
        for(int p = 2; p*p <=n; p++)
        {
            // If prime[p] is not changed, then it is a prime
            if(prime[p] == true)
            {
                // Update all multiples of p
                for(int i = p*p; i <= n; i += p)
                    prime[i] = false;
            }
        }
         
        // Print all prime numbers
        for(int i = 2; i <= n; i++)
        {
            if(prime[i] == true)
                System.out.print(i + " ");
        }
    }
     
    // Driver Program to test above function
    public static void main(String args[])
    {
        int n = 30;
        System.out.print("Following are the prime numbers ");
        System.out.println("smaller than or equal to " + n);
        SieveOfEratosthenes g = new SieveOfEratosthenes();
        g.sieveOfEratosthenes(n);
    }
}
 
// This code has been contributed by Amit Khandelwal.
Output
Following are the prime numbers smaller than or equal to 29
2 3 5 7 11 13 17 19 23 29 

Please refer complete article on Sieve of Eratosthenes for more details!
 




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