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Java Program For Rearranging A Linked List Such That All Even And Odd Positioned Nodes Are Together

Last Updated : 22 Jun, 2022
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Rearrange a linked list in such a way that all odd position nodes are together and all even positions node are together, 

Input:   1->2->3->4
Output:  1->3->2->4

Input:   10->22->30->43->56->70
Output:  10->30->56->22->43->70

The important thing in this question is to make sure that all below cases are handled 

  1. Empty linked list.
  2. A linked list with only one node.
  3. A linked list with only two nodes.
  4. A linked list with an odd number of nodes.
  5. A linked list with an even number of nodes.

The below program maintains two pointers ‘odd’ and ‘even’ for current nodes at odd and even positions respectively. We also store the first node of the even linked list so that we can attach the even list at the end of the odd list after all odd and even nodes are connected together in two different lists.


// Java program to rearrange a linked list
// in such a way that all odd positioned 
// node are stored before all even
// positioned nodes
class GfG {
// Linked List Node
static class Node
    int data;
    Node next;
// A utility function to create
// a new node
static Node newNode(int key)
    Node temp = new Node(); = key; = null;
    return temp;
// Rearranges given linked list
// such that all even positioned
// nodes are before odd positioned.
// Returns new head of linked List.
static Node rearrangeEvenOdd(Node head)
    // Corner case
    if (head == null)
        return null;
    // Initialize first nodes of even
    // and odd lists
    Node odd = head;
    Node even =;
    // Remember the first node of even
    // list so that we can connect the
    // even list at the end of odd list.
    Node evenFirst = even;
    while (1 == 1)
        // If there are no more nodes, 
        // then connect first node of even 
        // list to the last node of odd list
        if (odd == null || even == null ||
           ( == null)
   = evenFirst;
        // Connecting odd nodes =;
        odd =;
        // If there are NO more even
        // nodes after current odd.
        if ( == null)
   = null;
   = evenFirst;
        // Connecting even nodes =;
        even =;
    return head;
// A utility function to print
// a linked list
static void printlist(Node node)
    while (node != null)
        System.out.print( + "->");
        node =;
    System.out.println("NULL") ;
// Driver code
public static void main(String[] args)
    Node head = newNode(1); = newNode(2); = newNode(3); = newNode(4); = newNode(5);
    System.out.println("Given Linked List");
    head = rearrangeEvenOdd(head);
    System.out.println("Modified Linked List");
// This code is contributed by Prerna saini


Given Linked List
Modified Linked List

Time Complexity: O(n) where n is the number of nodes in the given linked list.
Auxiliary Space: O(1), no extra space is required, so it is a constant.

Please refer complete article on Rearrange a linked list such that all even and odd positioned nodes are together for more details!

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