Java Program for Left Rotation and Right Rotation of a String
Last Updated :
07 May, 2023
Given a string of size n, write functions to perform the following operations on a string-
- Left (Or anticlockwise) rotate the given string by d elements (where d <= n)
- Right (Or clockwise) rotate the given string by d elements (where d <= n).
Examples:
Input : s = "GeeksforGeeks"
d = 2
Output : Left Rotation : "eksforGeeksGe"
Right Rotation : "ksGeeksforGee"
Input : s = "qwertyu"
d = 2
Output : Left rotation : "ertyuqw"
Right rotation : "yuqwert"
Method 1:
A Simple Solution is to use a temporary string to do rotations. For left rotation, first, copy last n-d characters, then copy first d characters in order to the temporary string. For right rotation, first, copy last d characters, then copy n-d characters.
Can we do both rotations in-place and O(n) time?
The idea is based on a reversal algorithm for rotation.
// Left rotate string s by d (Assuming d <= n)
leftRotate(s, d)
reverse(s, 0, d-1); // Reverse substring s[0..d-1]
reverse(s, d, n-1); // Reverse substring s[d..n-1]
reverse(s, 0, n-1); // Reverse whole string.
// Right rotate string s by d (Assuming d <= n)
rightRotate(s, d)
// We can also call above reverse steps
// with d = n-d.
leftRotate(s, n-d)
Below is the implementation of the above steps :
Java
import java.util.*;
import java.io.*;
class GFG
{
static String leftrotate(String str, int d)
{
String ans = str.substring(d) + str.substring( 0 , d);
return ans;
}
static String rightrotate(String str, int d)
{
return leftrotate(str, str.length() - d);
}
public static void main(String args[])
{
String str1 = "GeeksforGeeks" ;
System.out.println(leftrotate(str1, 2 ));
String str2 = "GeeksforGeeks" ;
System.out.println(rightrotate(str2, 2 ));
}
}
|
Output
eksforGeeksGe
ksGeeksforGee
Time Complexity: O(N), as we are using a loop to traverse N times so it will cost us O(N) time.
Auxiliary Space: O(1), as we are not using any extra space.
Method 2:
We can use extended string which is double in size of normal string to rotate string. For left rotation, access the extended string from index n to the index len(string) + n. For right rotation, rotate the string left with size-d places.
Approach:
The approach is
// Left rotate string s by d
leftRotate(s, n)
temp = s + s; // extended string
l1 = s.length // length of string
return temp[n : l1+n] //return rotated string.
// Right rotate string s by n
rightRotate(s, n)
// We can also call above reverse steps
// with x = s.length - n.
leftRotate(s, x-n)
Below is implementation of above approach:
Java
import java.io.*;
import java.util.*;
class GFG {
static String leftrotate(String str1, int n)
{
String temp = str1 + str1;
int l1 = str1.length();
String Lfirst = temp.substring(n, n + l1);
return Lfirst;
}
static String rightrotate(String str1, int n)
{
return leftrotate(str1, str1.length() - n);
}
public static void main(String args[])
{
String str1 = "GeeksforGeeks" ;
System.out.println(leftrotate(str1, 2 ));
String str2 = "GeeksforGeeks" ;
System.out.println(rightrotate(str2, 2 ));
}
}
|
Output
eksforGeeksGe
ksGeeksforGee
Time Complexity: O(N), where N is the size of the given string.
Auxiliary Space: O(N)
Method 3:
This approach defines two functions for left and right rotation of a string using the deque. The left_rotate_string() function rotates the string s by d positions to the left, while the right_rotate_string() function rotates the string s by d positions to the right. Both functions return the rotated string.
Algorithm:
The algorithm is
- Define two functions for left rotation and right rotation which accept two arguments as input, a string “s” and an integer “d” which indicates the number of characters to be rotated.
- Create a deque object named “char_deque” of type Character using the ArrayDeque class.
- Add each character of the string to the deque object using a for-each loop.
- Perform a left rotation on the deque object by using a for loop to iterate through the deque “d” number of times. Within the for loop, remove the first element of the deque using “removeFirst()” method and add it to the end of the deque using “addLast()” method.
- Perform a right rotation on the deque object by using a for loop to iterate through the deque “d” number of times. Within the for loop, remove the last element of the deque using “removeLast()” method and add it to the beginning of the deque using “addFirst()” method.
- Convert the deque object back to a string using StringBuilder class and return it as a result of the function.
Below is implementation of above approach:
Java
import java.util.*;
public class GFG {
static String left_rotate_string(String s, int d)
{
Deque<Character> char_deque
= new ArrayDeque<Character>();
for ( char c : s.toCharArray()) {
char_deque.add(c);
}
for ( int i = 0 ; i < d; i++) {
char_deque.addLast(char_deque.removeFirst());
}
StringBuilder sb = new StringBuilder();
for ( char c : char_deque) {
sb.append(c);
}
return sb.toString();
}
static String right_rotate_string(String s, int d)
{
Deque<Character> char_deque
= new ArrayDeque<Character>();
for ( char c : s.toCharArray()) {
char_deque.add(c);
}
for ( int i = 0 ; i < d; i++) {
char_deque.addFirst(char_deque.removeLast());
}
StringBuilder sb = new StringBuilder();
for ( char c : char_deque) {
sb.append(c);
}
return sb.toString();
}
public static void main(String[] args)
{
String s = "GeeksforGeeks" ;
int d = 2 ;
System.out.println( "Left Rotation: "
+ left_rotate_string(s, d));
System.out.println( "Right Rotation: "
+ right_rotate_string(s, d));
s = "qwertyu" ;
d = 2 ;
System.out.println( "Left Rotation: "
+ left_rotate_string(s, d));
System.out.println( "Right Rotation: "
+ right_rotate_string(s, d));
}
}
|
Output
Left Rotation: eksforGeeksGe
Right Rotation: ksGeeksforGee
Left Rotation: ertyuqw
Right Rotation: yuqwert
Time complexity: O(n), where n is the length of the input string s. This is because the rotation operation requires visiting every character in the string exactly once.
Auxiliary Space: O(n)
Please refer complete article on Left Rotation and Right Rotation of a String for more details!
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