Java Program for Finding the vertex, focus and directrix of a parabola

A set of points on a plain surface that forms a curve such that any point on that curve is equidistant from the focus is a parabola.
Vertex of a parabola is the coordinate from which it takes the sharpest turn whereas a is the straight line used to generate the curve. The standard form of a parabola equation is . Given the values of a, b and c; our task is to find the coordinates of vertex, focus and the equation of the directrix.

Example –

Input : 5 3 2
Output : Vertex:(-0.3, 1.55)
Focus: (-0.3, 1.6)
Directrix: y=-198
Consult the formula below for explanation.

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

 // Java program to calculate Vertex, Focus and Directrix    public class TriangularPyramidNumber {     public static void parabola(float a, float b, float c)     {         System.out.println("Vertex: (" + (-b / (2 * a)) + ", "                            + (((4 * a * c) - (b * b)) / (4 * a)) + ")");            System.out.println("Focus: (" + (-b / (2 * a)) + ", "                            + (((4 * a * c) - (b * b) + 1) / (4 * a)) + ")");            System.out.println("Directrix: y="                            + (int)(c - ((b * b) + 1) * 4 * a));     }     public static void main(String[] args)     {         float a = 5, b = 3, c = 2;         parabola(a, b, c);     } }    // Contributed by _omg

Output:

Vertex: (-0.3, 1.55)
Focus: (-0.3, 1.6)
Directrix: y=-198

Please refer complete article on Finding the vertex, focus and directrix of a parabola for more details!

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