Java Program for Finding the vertex, focus and directrix of a parabola
A set of points on a plain surface that forms a curve such that any point on that curve is equidistant from the focus is a parabola.
Vertex of a parabola is the coordinate from which it takes the sharpest turn whereas a is the straight line used to generate the curve.
The standard form of a parabola equation is 
. Given the values of a, b and c; our task is to find the coordinates of vertex, focus and the equation of the directrix.
Example –
Input : 5 3 2
Output : Vertex:(-0.3, 1.55)
Focus: (-0.3, 1.6)
Directrix: y=-198
Consult the formula below for explanation.
Recommended: Please try your approach on {IDE} first, before moving on to the solution.
// Java program to calculate Vertex, Focus and Directrix public class TriangularPyramidNumber { public static void parabola(float a, float b, float c) { System.out.println("Vertex: (" + (-b / (2 * a)) + ", " + (((4 * a * c) - (b * b)) / (4 * a)) + ")"); System.out.println("Focus: (" + (-b / (2 * a)) + ", " + (((4 * a * c) - (b * b) + 1) / (4 * a)) + ")"); System.out.println("Directrix: y=" + (int)(c - ((b * b) + 1) * 4 * a)); } public static void main(String[] args) { float a = 5, b = 3, c = 2; parabola(a, b, c); } } // Contributed by _omg |
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Output:
Vertex: (-0.3, 1.55) Focus: (-0.3, 1.6) Directrix: y=-198
Please refer complete article on Finding the vertex, focus and directrix of a parabola for more details!
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