We can use binary search to reduce the number of comparisons in normal insertion sort. Binary Insertion Sort find use binary search to find the proper location to insert the selected item at each iteration.
In normal insertion, sort it takes O(i) (at ith iteration) in worst case. we can reduce it to O(logi) by using binary search.
// Java Program implementing // binary insertion sort import java.util.Arrays;
class GFG
{ public static void main(String[] args)
{
final int [] arr = { 37 , 23 , 0 , 17 , 12 , 72 , 31 ,
46 , 100 , 88 , 54 };
new GFG().sort(arr);
for ( int i= 0 ; i<arr.length; i++)
System.out.print(arr[i]+ " " );
}
public void sort( int array[])
{
for ( int i = 1 ; i < array.length; i++)
{
int x = array[i];
// Find location to insert using binary search
int j = Math.abs(Arrays.binarySearch(array, 0 , i, x) + 1 );
//Shifting array to one location right
System.arraycopy(array, j, array, j+ 1 , i-j);
//Placing element at its correct location
array[j] = x;
}
}
} // Code contributed by Mohit Gupta_OMG |
Please refer complete article on Binary Insertion Sort for more details!
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