Java long compareTo() with examples
Last Updated :
05 Dec, 2018
The java.lang.Long.compareTo() is a built-in method in java that compares two Long objects numerically. This method returns 0 if this object is equal to the argument object, it returns less than 0 if this object is numerically less than the argument object and a value greater than 0 if this object is numerically greater than the argument object.
Syntax:
public int compareTo(Object obj)
Parameter:
obj - The object which is to be compared to.
Returns: The function returns three values:
- equal to 0: Object is equal to the argument object
- less than 0: Object is less than the argument object
- greater than 0: Object is greater than the argument object
Program 1: The program below demonstrates the working of function.
import java.lang.Math;
class Gfg1 {
public static void main(String args[])
{
Long obj1 = new Long( 124 );
Long obj2 = new Long( 167 );
int compareValue = obj1.compareTo(obj2);
if (compareValue == 0 )
System.out.println( "object1 and object2 are equal" );
else if (compareValue < 0 )
System.out.println( "object1 is less than object2" );
else
System.out.println( "object1 is greater than object2" );
}
}
|
Output:
object1 is less than object2
Program 2: The program below demonstrates the working of function when no argument is passed
import java.lang.Math;
class Gfg1 {
public static void main(String args[])
{
Long obj1 = new Long( 124 );
Long obj2 = new Long( 167 );
int compareValue = obj1.compareTo();
if (compareValue == 0 )
System.out.println( "object1 and object2 are equal" );
else if (compareValue < 0 )
System.out.println( "object1 is less than object2" );
else
System.out.println( "object1 is greater than object2" );
}
}
|
Output:
prog.java:14: error: method compareTo in class Long cannot be applied to given types;
int compareValue = obj1.compareTo();
^
required: Long
found: no arguments
reason: actual and formal argument lists differ in length
1 error
Program 3: The program below demonstrates the working of function when anything other than object is passed in an argument
import java.lang.Math;
class Gfg1 {
public static void main(String args[])
{
Long obj1 = new Long( 124 );
int compareValue = obj1.compareTo( "gfg" );
if (compareValue == 0 )
System.out.println( "object1 and object2 are equal" );
else if (compareValue < 0 )
System.out.println( "object1 is less than object2" );
else
System.out.println( "object1 is greater than object2" );
}
}
|
Output:
prog.java:14: error: incompatible types: String cannot be converted to Long
int compareValue = obj1.compareTo("gfg");
^
Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output
1 error
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