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Java | Inheritance | Question 1
  • Difficulty Level : Medium
  • Last Updated : 24 Nov, 2013

Output of following Java Program?




class Base {
    public void show() {
       System.out.println("Base::show() called");
    }
}
   
class Derived extends Base {
    public void show() {
       System.out.println("Derived::show() called");
    }
}
   
public class Main {
    public static void main(String[] args) {
        Base b = new Derived();;
        b.show();
    }
}

(A) Derived::show() called
(B) Base::show() called


Answer: (A)

Explanation: In the above program, b is a reference of Base type and refers to an abject of Derived class.

In Java, functions are virtual by default. So the run time polymorphism happens and derived fun() is called.

Quiz of this Question

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