Open In App

Java | Inheritance | Question 1

Like Article
Like
Save Article
Save
Share
Report issue
Report

Output of following Java Program?




class Base {
    public void show() {
       System.out.println("Base::show() called");
    }
}
   
class Derived extends Base {
    public void show() {
       System.out.println("Derived::show() called");
    }
}
   
public class Main {
    public static void main(String[] args) {
        Base b = new Derived();;
        b.show();
    }
}


(A) Derived::show() called
(B) Base::show() called


Answer: (A)

Explanation: In the above program, b is a reference of Base type and refers to an object of Derived class.

In Java, functions are virtual by default. So the run time polymorphism happens and derived fun() is called.

Quiz of this Question


Last Updated : 09 Jul, 2021
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads