Java floor() method with Examples

The java.lang.Math.floor() returns the double value that is less than or equal to the argument and is equal to the nearest mathematical integer.
Note:

If the argument is Integer, then the result is Integer.
If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.

public static double floor(double a)
a : the argument whose floor value is to be determined
Returns : This method returns the double value that is less than or equal
to the argument and is equal to the nearest mathematical integer.

Example :To show working of java.lang.Math.floor() method.

// Java program to demonstrate working 
// of java.lang.Math.floor() method 
import java.lang.Math; 
  
class Gfg { 
  
    // driver code 
    public static void main(String args[]) 
    { 
        double a = 4.3; 
        double b = 1.0 / 0; 
        double c = 0.0; 
        double d = -0.0; 
        double e = -2.3; 
  
        System.out.println(Math.floor(a)); 
  
        // Input Infinity, Output Infinity 
        System.out.println(Math.floor(b)); 
  
        // Input Positive Zero, Output Positive Zero 
        System.out.println(Math.floor(c)); 
  
        // Input Negative Zero, Output Negative Zero 
        System.out.println(Math.floor(d)); 
  
        // Input -2.3, Output -3.0 
        // Nearest Integer(-3.0) < less than (-2.3) 
        System.out.println(Math.floor(e)); 
    } 
} 

Output:

4.0
Infinity
0.0
-0.0
-3.0

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