Java | Exception Handling | Question 8
class Test { public static void main (String[] args) { try { int a = 0 ; System.out.println ( "a = " + a); int b = 20 / a; System.out.println ( "b = " + b); } catch (ArithmeticException e) { System.out.println ( "Divide by zero error" ); } finally { System.out.println ( "inside the finally block" ); } } } |
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(A) Compile error
(B) Divide by zero error
(C)
a = 0 Divide by zero error inside the finally block
(D) a = 0
(E) inside the finally block
Answer: (C)
Explanation: On division of 20 by 0, divide by zero exception occurs and control goes inside the catch block.
Also, the finally block is always executed whether an exception occurs or not.
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