isunordered() function in C++
Last Updated :
26 Jun, 2023
The isunordered() function is defined in <cmath.h> and checks whether the value of first argument can be meaningfully compared with the second argument. If the first argument cannot be meaningfully compared with the second argument (i.e one or both are NAN), it return 1 otherwise 0.
Syntax:
bool isunordered(float x, float y);
or
bool isunordered(double x, double y);
Parameters: It takes two values x and y i.e values to check whether they are unordered.
Returns: It returns 1 if the value of x or y are NAN, Otherwise it returns 0.
Time Complexity: O(1)
Auxiliary Space: O(1)
Below programs illustrate the isunordered() function in C++:
Example 1:-
cpp
#include <bits/stdc++.h>
using namespace std;
int main()
{
float x=6.3;
float y= sqrt (-9);
cout<< "The value of x is= " << x << endl;
cout<< "The value of y is= " << y << endl;
cout<< "isunordered(x, y) = " <<isunordered(x, y);
return 0;
}
|
Output:
The value of x is= 6.3
The value of y is= -nan
isunordered(x, y) = 1
Explanation: In the example 1 the value of y is NAN thats why function returns 1.
Example 2:-
cpp
#include <bits/stdc++.h>
using namespace std;
int main()
{
float x=4.6;
float y=9.2;
cout<< "The value of x is= " << x << endl;
cout<< "The value of y is= " << y << endl;
cout<< "isunordered(x, y) = " <<isunordered(x, y);
return 0;
}
|
Output:
The value of x is= 4.6
The value of y is= 9.2
isunordered(x, y) = 0
Explanation: In the example 2 the value of x and y are not NAN thats why the function returns 0.
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