An array of 2 two byte integers is stored in big endian machine in byte address as shown below. What will be its storage pattern in little endian machine ?

Address Data
0 × 104 78
0 × 103 56
0 × 102 34
0 × 101 12 

(A)

0 × 104 12
0 × 103 56
0 × 102 34
0 × 101 78 

(B)

0 × 104 12
0 × 103 34
0 × 102 56
0 × 101 78 

(C)

0 × 104 56
0 × 103 78
0 × 102 12
0 × 101 34 

(D)

0 × 104 56
0 × 103 12
0 × 102 78
0 × 101 34 

Answer: (C)

Explanation: In little endian machines, last byte of binary representation of the multibyte data-type is stored first. On the other hand, in big endian machines, first byte of binary representation of the multibyte data-type is stored first.

Since, array of 2 two byte integers, so according to little endian,

0 × 104 56
0 × 103 78
0 × 102 12
0 × 101 34 

Option (C) is correct.

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