A particular disk unit uses a bit string to record the occupancy or vacancy of its tracks, with 0 denoting vacant and 1 for occupied. A 32-bit segment of this string has hexadecimal value D4FE2003. The percentage of occupied tracks for the corresponding part of the disk, to the nearest percentage is
Explanation: D4FE2003 = 1101 0100 1111 1110 0010 0000 0000 0011
Total bits = 32
Total bits which are occupied, i.e. with value 1 = 14
Percentage of occupied tracks = 14/32 * 100 = 43.75 = 44
So, option (D) is correct.
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