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ISRO | ISRO CS 2017 – May | Question 2
  • Last Updated : 20 Mar, 2018
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If A and B be two arbitrary events, then
(A) P(A ∩ B) = P(A)P(B)
(B) P(A ∪ B) = P(A) + P(B)
(C) P(A / B) = P(A ∩ B) + P(B)
(D) P(A ∪ B) <= P(A) + P(B)

Answer: (D)

Explanation: Case:1 P(A ∪ B) = P(A) + P(B) – P (A ∩ B).
Case:2 For two mutually exclusive events, (A ∩ B) = 0, So P(A ∪ B) <= P(A) + P(B) So, option (D) is correct.

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