Minimum number of multiplexers required to realize the following function,f = A’B’C + A’B’C’
Assume that inputs are available only in true form and Boolean constant 1 and 0 are available.
Explanation: The function can be simplified:
f = A’B'(C+C’) = A’B’
Since, we have to take the inputs in their true form(i.e, there is no way to get A’ or B’ directly), TWO Multiplexers will be required.
- 1st MUX will be used to get the function: AB
- 2nd MUX will be used to complement the output from the first, i.e, get A’B’
NOTE:There are other ways to solve this too.
I0 = 0
I1 = A
S = B
Output = 0 + AB = AB
I0 = 1
I1 = 0
S = AB (output from Mux1)
Output = (AB)’ = A’B’ (which is the desired output)