A certain population of ALOHA users manages to generate 70 request/sec. If the time is slotted in units of 50 msec, then channel load would be
Explanation: Number of requests = 70 request/sec
Time slot unit = 50 msec
Number of time slots in 1 second = 1000/50 = 20
Channel Load = Number of requests in 1 sec / Number of slots in 1 sec
= 70/20 = 3.5
Option (B) is correct.
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