ISRO | ISRO CS 2015 | Question 54

A certain population of ALOHA users manages to generate 70 request/sec. If the time is slotted in units of 50 msec, then channel load would be
(A) 4.25
(B) 3.5
(C) 350
(D) 450


Answer: (B)

Explanation: Number of requests = 70 request/sec
Time slot unit = 50 msec
Number of time slots in 1 second = 1000/50 = 20
Channel Load = Number of requests in 1 sec / Number of slots in 1 sec
= 70/20 = 3.5
Option (B) is correct.

Quiz of this Question
Please comment below if you find anything wrong in the above post