In a class B subnet, we know the IP address of one host and the mask as given below:
IP address: 18.104.22.168 Mask: 255.255.224.0
What is the first address(Network address)?
Explanation: We can obtain Network Address by performing bitwise and operation of IP address and Subnet Mask.
IP address: 22.214.171.124 Subnet Mask: 255.255.224.0 IP address: 01111101 10000110 01110000 01000010 Subnet Mask: 11111111 11111111 11100000 00000000 Network ID: 01111101 10000110 01100000 00000000
So, Network Address = 126.96.36.199
Option (A) is correct.
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