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ISRO | ISRO CS 2015 | Question 5
  • Last Updated : 20 Nov, 2018

The complement of the Boolean expression AB ( B’C + AC ) is
(A) ( A’ + B’ ) + ( B + C’ )( A’ + C’ )
(B) ( A’ + B’ ) + ( BC’ + A’C’ )
(C) ( A’ + B’ )( B + C’) + ( A + C’ )
(D) ( A + B )( B’ + C )( A + C )


Answer: (A)

Explanation: Applying DeMorgan’s law and after complementing: ( AB ( B’C + AC ))’
= (A + B)’ + (B’C + AC)’
= (A’ + B’) + ( B’C)’ (AC)’
= (A’ + B’) + ( B + C’)(A’ + C’)
Option (A) is correct.

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