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ISRO | ISRO CS 2014 | Question 77
  • Last Updated : 16 Apr, 2018

What is the size of the physical address space in a paging system which has a page table containing 64 entries of 11 bit each (including valid and invalid bit) and a page size of 512 bytes?
(A) 211
(B) 215
(C) 219
(D) 220


Answer: (C)

Explanation: Size of Physical Address = Paging bits + Offset bits
Paging bits = 11 – 1 = 10 (As 1 valid bit is also included)
Offset bits = log2page size = 9
Size of Physical Address = 10 + 9 = 19 bits
Option (C) is correct.

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