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ISRO | ISRO CS 2014 | Question 38
• Last Updated : 16 May, 2018

How many lines of output does the following C code produce?

 `#include``float` `i=2.0;``float` `j=1.0;``float` `sum = 0.0;``main()``{``    ``while` `(i/j > 0.001)``    ``{``        ``j+=j;``        ``sum=sum+(i/j);``        ``printf``(``"%f\n"``, sum);``    ``}``}`

(A) 8
(B) 9
(C) 10
(D) 11

Answer: (D)

Explanation: Given, i = 2.0 and j = 1.0.
Since “i” is not changing, to satisfy condition:

``` i/j > 0.001
→ 2.0/j > 0.001
→ 2.0/0.001 > j
→ 2000 > j ```

Value of “j” should be less than 2000 to satisfy given condition. Value of “j” is increasing in power of 2, i.e., 2n. So,

``` 2n > 2000
→ n > 10.9657
→ n = 11 ```

So, after 11th line while loop will terminate.
Actual output is:

```1.000000
1.500000
1.750000
1.875000
1.937500
1.968750
1.984375
1.992188
1.996094
1.998047
1.999023```

These are total 11 line.

So, option (D) is correct.

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