ISRO | ISRO CS 2014 | Question 38

How many lines of output does the following C code produce? 

C

#include
float i=2.0;
float j=1.0;
float sum = 0.0;
main()
{
while (i/j > 0.001)
{
j+=j;
sum=sum+(i/j);
printf(\”%f\\n\”, sum);
}
}

(A)

8

(B)

9

(C)

10

(D)

11

Answer: (D)

Explanation:

Given, i = 2.0 and j = 1.0. 
Since \”i\” is not changing, to satisfy condition: 

 i/j > 0.001 
→ 2.0/j > 0.001
→ 2.0/0.001 > j
→ 2000 > j 

Value of \”j\” should be less than 2000 to satisfy given condition. Value of \”j\” is increasing in power of 2, i.e., 2ⁿ. So, 

 2n > 2000
→ n > 10.9657
→ n = 11 

So, after 11th line while loop will terminate. 
Actual output is: 

1.000000
1.500000
1.750000
1.875000
1.937500
1.968750
1.984375
1.992188
1.996094
1.998047
1.999023

These are total 11 line. 

So, option (D) is correct.

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