ISRO | ISRO CS 2013 | Question 62
Consider the following C code.
#include
#include
void main()
{
double pi = 3.1415926535;
int a = 1;
int i;
for(i=0; i < 3; i++)
if(a = cos(pi * i/2) )
printf("%d ",1);
else printf("%d ", 0);
}
What would the program print?
(A) 000
(B) 010
(C) 101
(D) 111
Answer: (C)
Explanation: In first iteration: i = 0:
a = cos(pi * 0/2)
a = cos(0) = 1, condition true print 1
Second iteration: i = 1
a = cos (pi/2)
a = 0, so else part would print 0
Third iteration: i = 2
a = cos(pi)
a = -1, since any value other than 0
inside if statement returns true,
print 1
Output: 101
Option (C) is correct.
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Last Updated :
15 May, 2018
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