What is the maximum number of characters (7 bits + parity ) that can be transmitted in a second on a 19.2 kbps line. This asynchronous transmission requires 1 start bit and 1 stop bit.
Explanation: In asynchronous transmission mode, start bit and and stop bit is always required whereas in asynchronous mode these bits are not required.
So for this connection total number of bits in a character = 7 data bits + 1 parity bit + 1 start bit + 1 stop bit = 10 bits
Bandwidth = 19.2 kbps
Number of characters transmitted in 1 second = (19.2 *1000)/10 = 1920
Option (C) is correct.
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