Three coins are tossed simultaneously. The probability that they will fall two heads and one tail is
Explanation: Using Binomial Distribution, probability of 2 head and 1 tail:
nCk (p)k. (1-p)n-k
Here, n = 3, k = 2, prob(head) = p = 1/2, prob(tail) = (1-p) = 1/2
= 3C2 (1/2)2. (1/2)1 = 3 * (1/2)3 = 3/8
Option (D) is correct.
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