The cubic polynomial y(x) which takes the following values:
y(0) = 1, y(1) = 0, y(2) = 1 y(3) = 10 is
(A) x³ +2 x² + 1
(B) x³ + 3x² + 1
(C) x³ + 1
(D) x³ – 2 x² + 1


Answer: (D)

Explanation: The answer can be obtained by substituting the values of x and checking for y(x):
Option (D) is correct as:

x = 0: y(x) = 1
x = 1: y(x) = 0
x = 2: y(x) = 8 - 8 + 1 = 1
x = 3: y(x) = 27 - 18 + 1 = 10

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