ISRO | ISRO CS 2009 | Question 45
The cubic polynomial y(x) which takes the following values:
y(0) = 1, y(1) = 0, y(2) = 1 y(3) = 10 is
(A) x3 +2 x2 + 1
(B) x3 + 3x2 + 1
(C) x3 + 1
(D) x3 – 2 x2 + 1
Answer: (D)
Explanation: The answer can be obtained by substituting the values of x and checking for y(x):
Option (D) is correct as:
x = 0: y(x) = 1 x = 1: y(x) = 0 x = 2: y(x) = 8 - 8 + 1 = 1 x = 3: y(x) = 27 - 18 + 1 = 10