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ISRO | ISRO CS 2009 | Question 35

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Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data are stores in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk are respectively
(A) 256 Mbyte, 19 bits
(B) 256 Mbyte, 28 bit
(C) 512 Mbyte, 20 bits
(D) 64 Gbyte, 28 bits


Answer: (A)

Explanation: Capacity of the disk = 16 surfaces X 128 tracks X 256 sectors X 512 bytes = 256 Mbytes.
To calculate number of bits required to access a sector, we need to know total number of sectors. Total number of sectors = 16 surfaces X 128 tracks X 256 sectors = 2^19
So the number of bits required to access a sector is 19.

Option (A) is correct.

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Last Updated : 05 Jun, 2018
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