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ISRO | ISRO CS 2007 | Question 18

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The number of digit 1 present in the binary representation of

3 × 512 + 7 × 64 + 5 × 8 + 3

(A)

8

(B)

9

(C)

10

(D)

12


Answer: (B)

Explanation:

3 × 512 + 7 × 64 + 5 × 8 + 3
= (2 + 1)× 512 + (4 + 2 + 1)× 64 + (4 + 1)× 8 + 2 + 1

= 1024 + 512 + 64 x 4 + 64 x 2 + 64 + 32 + 8 + 2 + 1 = 1024 + 512 + 256 + 128 + 64 + 32 + 8 + 2 + 1 As 1024 has ten 0\’s followed by 1, 512 has nine 0\’s followed by 1 and so on.. So, the expression will contain total nine 1\’s and will be represented as 11111101011. Option (B) is correct.


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Last Updated : 20 Nov, 2018
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