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ispunct() function in C

  • Difficulty Level : Easy
  • Last Updated : 09 Nov, 2021

The ispunct() function checks whether a character is a punctuation character or not. 
The term “punctuation” as defined by this function includes all printable characters that are neither alphanumeric nor a space. For example ‘@’, ‘$’, etc. 
This function is defined in ctype.h header file.
 

syntax:

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int ispunct(int ch);
ch: character to be checked.
Return Value  : function return nonzero
 if character is a punctuation character;
 otherwise zero is returned. 

 

CPP




// Program to check punctuation
#include <stdio.h>
#include <ctype.h>
int main()
{
    // The punctuations in str are '!' and ','
    char str[] = "welcome! to GeeksForGeeks, ";
 
    int i = 0, count = 0;
    while (str[i]) {
        if (ispunct(str[i]))
            count++;
        i++;
    }
    printf("Sentence contains %d punctuation"
           " characters.\n", count);
    return 0;
}

Output:  

Sentence contains 2 punctuation characters.

C




// C program to print all Punctuations
#include <stdio.h>
#include <ctype.h>
int main()
{
    int i;
    printf("All punctuation characters in C"
            " programming are: \n");
    for (i = 0; i <= 255; ++i)
        if (ispunct(i) != 0)
            printf("%c ", i);
    return 0;
}

Output: 

All punctuation characters in C programming are: 
! " # $ % & ' ( ) * +, - . / : ;  ? @ [ \ ] ^ _ ` { | } ~

This article is contributed by Shivani Ghughtyal. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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