The ispunct() function checks whether a character is a punctuation character or not.
The term “punctuation” as defined by this function includes all printable characters that are neither alphanumeric nor a space. For example ‘@’, ‘$’, etc.
This function is defined in ctype.h header file.
syntax:
int ispunct(int ch);
ch: character to be checked.
Return Value : function return nonzero
if character is a punctuation character;
otherwise zero is returned.
CPP
#include <stdio.h>
#include <ctype.h>
int main()
{
char str[] = "welcome! to GeeksForGeeks, " ;
int i = 0, count = 0;
while (str[i]) {
if (ispunct(str[i]))
count++;
i++;
}
printf ( "Sentence contains %d punctuation"
" characters.\n" , count);
return 0;
}
|
Output:
Sentence contains 2 punctuation characters.
CPP
#include <stdio.h>
#include <ctype.h>
int main()
{
int i;
printf ( "All punctuation characters in C"
" programming are: \n" );
for (i = 0; i <= 255; ++i)
if (ispunct(i) != 0)
printf ( "%c " , i);
return 0;
}
|
Output:
All punctuation characters in C programming are:
! " # $ % & ' ( ) * +, - . / : ; ? @ [ \ ] ^ _ ` { | } ~
Last Updated :
16 Dec, 2021
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