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ispunct() function in C

  • Difficulty Level : Easy
  • Last Updated : 03 Oct, 2017
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The ispunct() function checks whether a character is a punctuation character or not.
The term “punctuation” as defined by this function includes all printable characters that are neither alphanumeric nor a space. For example ‘@’, ‘$’, etc.
This function is defined in ctype.h header file.


int ispunct(int ch);
ch: character to be checked.
Return Value  : function return nonzero
 if character is a punctuation character;
 otherwise zero is returned. 

// Program to check punctuation
#include <stdio.h>
#include <ctype.h>
int main()
    // The puncuations in str are '!' and ','
    char str[] = "welcome! to GeeksForGeeks, ";
    int i = 0, count = 0;
    while (str[i]) {
        if (ispunct(str[i]))
    printf("Sentence contains %d punctuation"
           " characters.\n", count);
    return 0;


Sentence contains 2 punctuation characters.

// C program to print all Punctuations
#include <stdio.h>
#include <ctype.h>
int main()
    int i;
    printf("All punctuation characters in C"
            " programming are: \n");
    for (i = 0; i <= 255; ++i)
        if (ispunct(i) != 0)
            printf("%c ", i);
    return 0;


All punctuation characters in C programming are: 
! " # $ % & ' ( ) * +, - . / : ;  ? @ [ \ ] ^ _ ` { | } ~

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